document.write( "Question 121192: A guy wire of length 50 feet is attached to the ground and to the top of an antenna. The height of the antenna is 10 feet larger than the distance from the base of the antenna to the point where the guy wire is attached to the ground. What is the height of the antenna? \n" ); document.write( "
Algebra.Com's Answer #88919 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! A^2+B^2=C^2 \n" ); document.write( "A^2+(A+10)^2=50^2 \n" ); document.write( "A^2+A^2+20A+100=2500 \n" ); document.write( "2A^2+20A+100-2500=0 \n" ); document.write( "2A^2+20A-2400=0 \n" ); document.write( "2(A^2+10A-1200)=0 \n" ); document.write( "2(A+40)(A-30)=0 \n" ); document.write( "A-30=0 \n" ); document.write( "A=30 FEET IS THE DISTANCE FROM THE BASE OF THE ANTENNA TO THE GUIDE WIRE. \n" ); document.write( "THEREFORE THE HEIGHT OF THE ANTENNAIS: \n" ); document.write( "30+10=40 FEET FOR THE HEIGHT. \n" ); document.write( "PROOF \n" ); document.write( "30^2+40^2=50^2 \n" ); document.write( "900+1600=2500 \n" ); document.write( "2500=2500 \n" ); document.write( " |