document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121162>Question 121162</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cyclist traveled at a rate of 24 mph to visit a nearby town.  The cyclist averaged 18 mph on the return trip.  If the round trip took 4.9 hours, find the distance to the nearby town?  [I need the correct college algebra equation of the form D = rt] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88896 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "SEEING AS THE DISTANCES ARE THE SAME WE HAVE:<BR>\n" );
document.write( "24X=18(4.9-X)<BR>\n" );
document.write( "24X=88.2-18X<BR>\n" );
document.write( "24X+18X=88.2<BR>\n" );
document.write( "42X=88.2<BR>\n" );
document.write( "X=88.2/42<BR>\n" );
document.write( "X=2.1 HOURS FOR THE 24 MPH TRIP.<BR>\n" );
document.write( "4.9-2.1=2.8 HOURS FOR THE 18 MPH TRIP.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "24*2.1=18*2.8<BR>\n" );
document.write( "50.4=50.4 THEREFORE THE DISTANCE TO THE NEARBY TOWN IS 50.4 MILES.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );