document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121020>Question 121020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each system by the substitution method.\r<BR>\n" );
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document.write( "3x+y=2<BR>\n" );
document.write( "-x-3y=6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88879 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88879\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3X+Y=2 OR Y=-3X+2 NOW SUBSTITUTE (-3X+2) FOR Y IN THE OTHER EQUATION:<BR>\n" );
document.write( "-X-3(-3X+2)=6<BR>\n" );
document.write( "-X+9X-6=6<BR>\n" );
document.write( "8X=6+6<BR>\n" );
document.write( "8X=12<BR>\n" );
document.write( "X=12/8<BR>\n" );
document.write( "X=1.5 ANSWER.<BR>\n" );
document.write( "Y=-3*1.5+2<BR>\n" );
document.write( "Y=-4.5+2<BR>\n" );
document.write( "Y=-2.5 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "-1.5-3*-2.5=6<BR>\n" );
document.write( "-1.5+7.5=6<BR>\n" );
document.write( "6=6 </SPAN>\n" );
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