document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121024>Question 121024</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The  acient Greeks thought that the most pleasing shape for a rectangle was one for which the ratio of the length to the width was 8 to 5, the golden ratio. If the length of the painting is 2 ft longer than its width, then for what dimensions would the length and width have the golden ratio?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88876 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88876\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8/5=(X+2)/X NOW CROSS MULTIPLY.<BR>\n" );
document.write( "8X=5(X+2)<BR>\n" );
document.write( "8X=5X+10<BR>\n" );
document.write( "8X-5X=10<BR>\n" );
document.write( "3X=10<BR>\n" );
document.write( "X=10/3<BR>\n" );
document.write( "X=3.333<BR>\n" );
document.write( "3.333+2=5.333<BR>\n" );
document.write( "THUS THE GOLDEN RATIO HERE IS 3.333 BY 5.333.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "8/5=5.333/3.333<BR>\n" );
document.write( "1.6=1.6 <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );