document.write( "Question 121083: If the surface area of a right circular cylinder is 12pie and the height is 1, what is its radius?\r
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Algebra.Com's Answer #88824 by solver91311(24713)\"\" \"About 
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You don't specify whether you want the lateral surface area or the total surface area:\r
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\n" ); document.write( "\n" ); document.write( "For the lateral surface area:\r
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\n" ); document.write( "\n" ); document.write( "\"A=2%28pi%29rh\".\r
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\n" ); document.write( "\n" ); document.write( "For \"h+=+1\" and \"A=12%28pi%29\", this becomes\r
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\n" ); document.write( "\n" ); document.write( "\"2%28pi%29r=12%28pi%29\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by \"2%28pi%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r=6\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore, if the lateral surface area is \"12%28pi%29\", then the radius is 6\r
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\n" ); document.write( "\n" ); document.write( "For the total surface area:\r
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\n" ); document.write( "\n" ); document.write( "\"A=2%28pi%29r%5E2%2B2%28pi%29rh\", again substituting \"h+=+1\" and \"A=12%28pi%29\", we get:\r
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\n" ); document.write( "\n" ); document.write( "\"2%28pi%29r%5E2%2B2%28pi%29r=12%28pi%29\"\r
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\n" ); document.write( "\n" ); document.write( "Again, divide by \"2%28pi%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r%5E2%2Br=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"r%5E2%2Br-6=0\"\r
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\n" ); document.write( "\n" ); document.write( "Factor\r
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\n" ); document.write( "\n" ); document.write( "\"%28r%2B3%29%28r-2%29=0\", so \"r=-3\" or \"r=2\".\r
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\n" ); document.write( "\n" ); document.write( "We can exclude \"r=-3\" because we are looking for a positive number measurement of length.\r
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\n" ); document.write( "\n" ); document.write( "Therefore if the total surface area is \"12%28pi%29\", the radius is \"2\"
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