document.write( "Question 120979: the process is elimination by substitution. Equation(1) x+y over 2 minus x-y over 3 equals 8. Equation(2) x+y over 3 plus x-y over 4 equals 11 \n" ); document.write( "
Algebra.Com's Answer #88756 by edjones(8007)\"\" \"About 
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1)
\n" ); document.write( "(x+y)/2-(x-y)/3=8
\n" ); document.write( "6(x+y)/2-6(x-y)/3=6*8
\n" ); document.write( "3(x+y)-2(x-y)=48 No fractions.
\n" ); document.write( "3x+3y-2x+2y=48
\n" ); document.write( "x+5y=48
\n" ); document.write( "x=48-5y
\n" ); document.write( ".
\n" ); document.write( "2)
\n" ); document.write( "(x+y)/3+(x-y)/4=11
\n" ); document.write( "12(x+y)/3+12(x-y)/4=12*11
\n" ); document.write( "4(x+y)+3(x-y)=132
\n" ); document.write( "4x+4y+3x-3y=132
\n" ); document.write( "7x+y=132
\n" ); document.write( "7(48-5y)+y=132 substitute.
\n" ); document.write( "336-35y+y=132
\n" ); document.write( "336-336-34y=132-336
\n" ); document.write( "-34y=-204
\n" ); document.write( "-34y/-34=-204/-34
\n" ); document.write( "y=6
\n" ); document.write( ".
\n" ); document.write( "x=48-5y
\n" ); document.write( "x=48-5*6
\n" ); document.write( "=48-30
\n" ); document.write( "=18
\n" ); document.write( ".
\n" ); document.write( "Check:
\n" ); document.write( "(x+y)/3+(x-y)/4=11
\n" ); document.write( "(18+6)/3+(18-6)/4=11
\n" ); document.write( "8+3=11 true
\n" ); document.write( ".
\n" ); document.write( "Ed\r
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