document.write( "Question 120962: 1/a=1/b+1/c for B \n" ); document.write( "

Algebra.Com's Answer #88753 by edjones(8007) $\"\"$ $\"About$

You can put this solution on YOUR website!
1/a=1/b+1/c
\n" ); document.write( "abc/a=abc/b+abc/c
\n" ); document.write( "bc=ac+ab Fractions gone.
\n" ); document.write( "bc-ab=ac+ab-ab
\n" ); document.write( "bc-ab=ac
\n" ); document.write( "b(c-a)=ac
\n" ); document.write( "b(c-a)/(c-a)=ac/(c-a)
\n" ); document.write( "b=ac/(c-a)
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\n" ); document.write( "Ed \n" ); document.write( "

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