document.write( "Question 120932: fine three consecutive even integers such that the sum of the smallest and twice the second is 20 more than the third \n" ); document.write( "
Algebra.Com's Answer #88734 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! X, X+1 & X+2 ARE THE 3 CONSECUTIVE INTEGERS. \n" ); document.write( "X+2(X+1)=(X+2)+20 \n" ); document.write( "X+2X+2=X+2+20 \n" ); document.write( "X+2X-X=2+20-2 \n" ); document.write( "2X=20 \n" ); document.write( "X=20/1 \n" ); document.write( "X=10 ANSWER FORT THE SMALLEST INTEGER. \n" ); document.write( "10+1=11 FOR THE NEXT INTEGER. \n" ); document.write( "10+2=12 FOR THE LARGEST INTEGER. \n" ); document.write( "PROOF \n" ); document.write( "10+2*11=12+20 \n" ); document.write( "10+22+32 \n" ); document.write( "32=32 \n" ); document.write( " \n" ); document.write( " |