document.write( "Question 120932: fine three consecutive even integers such that the sum of the smallest and twice the second is 20 more than the third \n" ); document.write( "
Algebra.Com's Answer #88734 by checkley71(8403)\"\" \"About 
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X, X+1 & X+2 ARE THE 3 CONSECUTIVE INTEGERS.
\n" ); document.write( "X+2(X+1)=(X+2)+20
\n" ); document.write( "X+2X+2=X+2+20
\n" ); document.write( "X+2X-X=2+20-2
\n" ); document.write( "2X=20
\n" ); document.write( "X=20/1
\n" ); document.write( "X=10 ANSWER FORT THE SMALLEST INTEGER.
\n" ); document.write( "10+1=11 FOR THE NEXT INTEGER.
\n" ); document.write( "10+2=12 FOR THE LARGEST INTEGER.
\n" ); document.write( "PROOF
\n" ); document.write( "10+2*11=12+20
\n" ); document.write( "10+22+32
\n" ); document.write( "32=32
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