document.write( "Question 120936: A consumer electronics company sells 6.7 million MP3 players per month at a price of $100 apiece; when the price is lowered to $80, the company sells 10.2 million players per month. How many MP3 players can the company expect to sell per month at a price of $75? \n" ); document.write( "
Algebra.Com's Answer #88729 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A consumer electronics company sells 6.7 million MP3 players per month at a price of $100 apiece; when the price is lowered to $80, the company sells 10.2 million players per month. How many MP3 players can the company expect to sell per month at a price of $75? \n" ); document.write( "---------------------------------- \n" ); document.write( "You have two points : (100,6.7) and (80,10.2) \n" ); document.write( "----------------------- \n" ); document.write( "slope = (10.2-6.7)/(80-100) = 3.5/-20 = -7/40 \n" ); document.write( "--------------------- \n" ); document.write( "equation form: # = (slope)*(price) + b \n" ); document.write( "Substitute to solve for \"b\": \n" ); document.write( "6.7 = (-7/40)*100 + b \n" ); document.write( "b = 24.20 \n" ); document.write( "------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "Let price be \"x\"; Let # sold be \"y\" \n" ); document.write( "f(x) = (-7/40)x+24.20 \n" ); document.write( "----------------------- \n" ); document.write( "f(75) = (-7/40)*75+24.2 \n" ); document.write( "f(75) = 11.0750 million \n" ); document.write( "---------------- \n" ); document.write( "Conclusion: When the price is $75 the # sold is 11.075 million \n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |