document.write( "Question 120936: A consumer electronics company sells 6.7 million MP3 players per month at a price of $100 apiece; when the price is lowered to $80, the company sells 10.2 million players per month. How many MP3 players can the company expect to sell per month at a price of $75? \n" ); document.write( "
Algebra.Com's Answer #88729 by stanbon(75887)\"\" \"About 
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A consumer electronics company sells 6.7 million MP3 players per month at a price of $100 apiece; when the price is lowered to $80, the company sells 10.2 million players per month. How many MP3 players can the company expect to sell per month at a price of $75?
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\n" ); document.write( "You have two points : (100,6.7) and (80,10.2)
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\n" ); document.write( "slope = (10.2-6.7)/(80-100) = 3.5/-20 = -7/40
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\n" ); document.write( "equation form: # = (slope)*(price) + b
\n" ); document.write( "Substitute to solve for \"b\":
\n" ); document.write( "6.7 = (-7/40)*100 + b
\n" ); document.write( "b = 24.20
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\n" ); document.write( "EQUATION:
\n" ); document.write( "Let price be \"x\"; Let # sold be \"y\"
\n" ); document.write( "f(x) = (-7/40)x+24.20
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\n" ); document.write( "f(75) = (-7/40)*75+24.2
\n" ); document.write( "f(75) = 11.0750 million
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\n" ); document.write( "Conclusion: When the price is $75 the # sold is 11.075 million
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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