document.write( "Question 120938: The length of a rectangle is 1 cm more than 5 times its width. If the area of the rectangle is 79 cm2, find the dimensions of the rectangle to the nearest thousandth.\r
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document.write( "I get so confused on these questions. I am just lost on this. Please help!!! \n" );
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Algebra.Com's Answer #88721 by stanbon(75887) ![]() You can put this solution on YOUR website! The length of a rectangle is 1 cm more than 5 times its width. If the area of the rectangle is 79 cm2, find the dimensions of the rectangle to the nearest thousandth. \n" ); document.write( "------------------- \n" ); document.write( "Formula: Area = (length)*(width) \n" ); document.write( "-------------- \n" ); document.write( "Let the width be \"x\" cm. ; Then length = \"5x+1\" cm. \n" ); document.write( "------------ \n" ); document.write( "Your Problem: \n" ); document.write( "79 cm^2 = (5x+1)*x \n" ); document.write( "79 = 5x^2+x \n" ); document.write( "5x^2+x-79=0 \n" ); document.write( "x = [-1 +- sqrt(1-4*5*-79)]/10 \n" ); document.write( "x = [-1 +- sqrt(1581)]/10 \n" ); document.write( "x = [-1 +- 39.7618]/10 \n" ); document.write( "x = 3.8762 cm (The width of the rectangle) \n" ); document.write( "5x+1 = 20.3809 cm (The length of the rectangle) \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " \n" ); document.write( " |