document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=120927>Question 120927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm also having trouble with this problem. I've tried cross multiplying, but I don't think that's what I'm supposed to do.\r<BR>\n" );
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document.write( "2x     2<BR>\n" );
document.write( "--- = ---<BR>\n" );
document.write( " 3    3x-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88714 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x/3=2/(3x-1) now cross multiply.<BR>\n" );
document.write( "2x(3x-1)=3*2<BR>\n" );
document.write( "6x^2-2x-6=0<BR>\n" );
document.write( "2(3x^2-x-3)=0 USING THE QUADRATIC EQUATION.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >  WE GET.<BR>\n" );
document.write( "X=(1+-SQRT[-1^2-4*3*-3])/2*3<BR>\n" );
document.write( "X=(1+-SQRT1+36])/6<BR>\n" );
document.write( "X=(1+-SQRT370/6<BR>\n" );
document.write( "X=(1+-6.08)/6<BR>\n" );
document.write( "X=(1+6.08)/6<BR>\n" );
document.write( "X=7.08/6<BR>\n" );
document.write( "X=1.18 ANSWER.<BR>\n" );
document.write( "X=1-6.08)/6<BR>\n" );
document.write( "X=-5.08/6<BR>\n" );
document.write( "X=-.84 ANSWER.<BR>\n" );
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