document.write( "Question 120832: 4
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\n" ); document.write( "3n
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\n" ); document.write( "\n" ); document.write( "2
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\n" ); document.write( "n+1
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\n" ); document.write( "\n" ); document.write( "2
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\n" ); document.write( "n^2+n
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Algebra.Com's Answer #88688 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Assume you mean:
\n" ); document.write( "\"4%2F%283n%29\" + \"2%2F%28%28n%2B1%29%29\" + \"2%2F%28%28n%5E2%2Bn%29%29\"
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\n" ); document.write( "Factor out n in the 3rd denominator:
\n" ); document.write( "\"4%2F%283n%29\" + \"2%2F%28%28n%2B1%29%29\" + \"2%2F%28n%28n%2B1%29%29\"
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\n" ); document.write( "The common denominator will be: 3n(n+1), so we have:
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\n" ); document.write( "\"%284%28n%2B1%29+%2B+2%283n%29+%2B+3%282%29%29%2F%283n%28n%2B1%29%29\" = \"%284n+%2B+4+%2B+6n+%2B+6%29%2F%283n%28n%2B1%29%29\" = \"%2810n+%2B+10%29%2F%283n%28n%2B1%29%29\" = \"%2810%28n+%2B+1%29%29%2F%283n%28n%2B1%29%29\"
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\n" ); document.write( "The (n+1)'s cancel, we are left with:
\n" ); document.write( "\"10%2F%283n%29\"
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\n" ); document.write( "How about this? Could you follow this ok? Any questions? Let me know.
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