document.write( "Question 120868This question is from textbook college algebra
\n" ); document.write( ": Could you please help solve for this problem it has 4 parts? I don't know where to start.\r
\n" ); document.write( "\n" ); document.write( "The path of a falling object is given by the function s=-16t^2+v0t+s0 where v0 represents the initial velocity in ft/sec and s0 represents the initial height. The variable t is time in seconds, and the s is the height of the object in feet.
\n" ); document.write( "a) If a rock is thrown upward with an initial velocity of 32 feet per second from the top of a 40-foot building, write the height equation using this information.\r
\n" ); document.write( "\n" ); document.write( "b) How high is the rock after 0.5 seconds?\r
\n" ); document.write( "\n" ); document.write( "c) After how many sections will the rock reach maximum height?\r
\n" ); document.write( "\n" ); document.write( "d)What is the maximum height?\r
\n" ); document.write( "\n" ); document.write( "Please show all work
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Algebra.Com's Answer #88672 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"s%28t%29=-16t%5E2%2Bv%5B0%5Dt%2Bs%5B0%5D\"\r
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\n" ); document.write( "\n" ); document.write( "a. You are given that \"v%5B0%5D=32\" and \"s%5B0%5D=40\", so just plug in the values:\r
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\n" ); document.write( "\n" ); document.write( "\"s%28t%29=-16t%5E2%2B32t%2B40\"\r
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\n" ); document.write( "\n" ); document.write( "b. You need to evaluate \"s%280.5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"s%280.5%29=-16%280.5%29%5E2%2B32%280.5%29%2B40\"
\n" ); document.write( "\"s%280.5%29=-16%280.25%29%2B32%280.5%29%2B40\"
\n" ); document.write( "\"s%280.5%29=-4%2B16%2B40\"
\n" ); document.write( "\"s%280.5%29=52\"\r
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\n" ); document.write( "\n" ); document.write( "So the height (measured from the ground) after one-half second is 52 feet.\r
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\n" ); document.write( "\n" ); document.write( "c. This is a quadratic equation and if you graphed it on a coordinate plane with s as the vertical axis and t as the horizontal axis, you would have a convex down parabola. The maximum height will be reached at time equal to the value of t at the vertex of the parabola.\r
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\n" ); document.write( "\n" ); document.write( "The vertex of any parabola described by \"f%28x%29=ax%5E2%2Bbx%2Bc\" is located at (\"%28-b%29%2F2a%29\",\"f%28%28-b%29%2F2a%29\")\r
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\n" ); document.write( "\n" ); document.write( "For this problem, \"a=-16\" and \"b=32\", hence \"t%5Bmaxh%5D=%28-32%29%2F%282%2A%28-16%29%29=%28-32%29%2F-32=1\" second.\r
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\n" ); document.write( "You can also do this part with the calculus\r
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\n" ); document.write( "\n" ); document.write( "A local minimum or maximum is found where the first derivative equals 0.\r
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\n" ); document.write( "\n" ); document.write( "For this problem, s'(t)=\"-32t%2B32\", so if \"-32t%2B32=0\" then \"x=1\"\r
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\n" ); document.write( "\n" ); document.write( "To determine if this is a maximum or minimum, evaluate the second derivative at the same value\r
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\n" ); document.write( "\n" ); document.write( "s\"(t)=\"-32\". Since the second derivitive is less than zero, this is a maximum.\r
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\n" ); document.write( "\n" ); document.write( "d. The actual maximum height is just the function evaluated at the time for maximum height, i.e. 1 second, or \"s%281%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"s%281%29=-16%281%29%5E2%2B32%281%29%2B40\"
\n" ); document.write( "\"s%281%29=-16%2B32%2B40\"
\n" ); document.write( "\"s%281%29=56\"\r
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\n" ); document.write( "\n" ); document.write( "And the maximum height is 56 feet.
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