document.write( "Question 120735: Solve each system by the addition method.\r
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document.write( "(1/8)x+(1/4)y=3
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document.write( "(1/16)x+(1/2)y=7\r
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document.write( "and\r
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document.write( "1.5x-2y=-0.25
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document.write( "3x+1.5Y=6.375 \n" );
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Algebra.Com's Answer #88666 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! x/8+y/4=3 \n" ); document.write( "x/16+y/2=7 now multiply the second equation by -1/2 & add. \n" ); document.write( "x/8+y/4=3 \n" ); document.write( "-x/32-y/4=-7/2 \n" ); document.write( "-------------------------------------- \n" ); document.write( "x/8-x/32=3-7/2 \n" ); document.write( "4x/32-x/32=6/2-7/2 \n" ); document.write( "3x/32=-1/2 now cross multiply. \n" ); document.write( "3x*2=-32 \n" ); document.write( "6x=-32 \n" ); document.write( "x=-32/6 \n" ); document.write( "x=-16/3 answer. \n" ); document.write( "-16/3*1/8+y/4=3 \n" ); document.write( "-16/24+y/4=3 \n" ); document.write( "y/4=3+16/24 \n" ); document.write( "y/4=3+2/3 \n" ); document.write( "y/4=9/3+2/3 \n" ); document.write( "y/4=11/3 cross multiply \n" ); document.write( "3y=44 \n" ); document.write( "y=44/3 answer. \n" ); document.write( "proof \n" ); document.write( "(-16/3)/16+(44/3)/2=7 \n" ); document.write( "-1/3+44/6=7 \n" ); document.write( "-1/3+22/3=7 \n" ); document.write( "21/3=7 \n" ); document.write( "7=7 \n" ); document.write( " |