document.write( "Question 120735: Solve each system by the addition method.\r
\n" ); document.write( "\n" ); document.write( "(1/8)x+(1/4)y=3
\n" ); document.write( "(1/16)x+(1/2)y=7\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "1.5x-2y=-0.25
\n" ); document.write( "3x+1.5Y=6.375
\n" ); document.write( "

Algebra.Com's Answer #88666 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
x/8+y/4=3
\n" ); document.write( "x/16+y/2=7 now multiply the second equation by -1/2 & add.
\n" ); document.write( "x/8+y/4=3
\n" ); document.write( "-x/32-y/4=-7/2
\n" ); document.write( "--------------------------------------
\n" ); document.write( "x/8-x/32=3-7/2
\n" ); document.write( "4x/32-x/32=6/2-7/2
\n" ); document.write( "3x/32=-1/2 now cross multiply.
\n" ); document.write( "3x*2=-32
\n" ); document.write( "6x=-32
\n" ); document.write( "x=-32/6
\n" ); document.write( "x=-16/3 answer.
\n" ); document.write( "-16/3*1/8+y/4=3
\n" ); document.write( "-16/24+y/4=3
\n" ); document.write( "y/4=3+16/24
\n" ); document.write( "y/4=3+2/3
\n" ); document.write( "y/4=9/3+2/3
\n" ); document.write( "y/4=11/3 cross multiply
\n" ); document.write( "3y=44
\n" ); document.write( "y=44/3 answer.
\n" ); document.write( "proof
\n" ); document.write( "(-16/3)/16+(44/3)/2=7
\n" ); document.write( "-1/3+44/6=7
\n" ); document.write( "-1/3+22/3=7
\n" ); document.write( "21/3=7
\n" ); document.write( "7=7
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