document.write( "Question 120847: The numerator of a fraction is seven more than twice the denominator. The value of the reciprocal of the fraction is 0.4. Find the original fraction.\r
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Algebra.Com's Answer #88645 by solver91311(24713)\"\" \"About 
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Let x be the denominator. Twice the denominator is then 2x and seven more than that is 2x + 7, so our fraction is \"%282x%2B7%29%2Fx\".\r
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\n" ); document.write( "\n" ); document.write( "Since the value of the reciprocal of the fraction is 0.4, we can represent the reciprocal as \"4%2F10\". Therefore the value of the fraction itself must be \"10%2F4\".\r
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\n" ); document.write( "\n" ); document.write( "Now we have enough information to create an equation:\r
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\n" ); document.write( "\n" ); document.write( "\"%282x%2B7%29%2Fx=10%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by 4, and then multiply both sides by x:\r
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\n" ); document.write( "\n" ); document.write( "\"4%282x%2B7%29=10x\"\r
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\n" ); document.write( "\n" ); document.write( "Distribute:\r
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\n" ); document.write( "\n" ); document.write( "\"8x%2B28=10x\"\r
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\n" ); document.write( "\n" ); document.write( "Add -10x to both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"-10x%2B8x%2B28=10x-10x\"
\n" ); document.write( "\"-2x%2B28=0\"\r
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\n" ); document.write( "\n" ); document.write( "Add -28 to both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"-2x=-28\"\r
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\n" ); document.write( "\n" ); document.write( "Divide by -2:\r
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\n" ); document.write( "\n" ); document.write( "\"x=14\"\r
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\n" ); document.write( "\n" ); document.write( "Check the answer:\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2814%29%2B7%29%2F14=35%2F14=5%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%2F5=0.4\", answer checks.
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