document.write( "Question 120847: The numerator of a fraction is seven more than twice the denominator. The value of the reciprocal of the fraction is 0.4. Find the original fraction.\r
\n" ); document.write( "\n" ); document.write( "Could someone please help me?
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Algebra.Com's Answer #88644 by Earlsdon(6294)\"\" \"About 
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Let N = the numerator and D = the denominator, so the fraction can be written as: \"N%2FD\".
\n" ); document.write( "From the problem, you can write:
\n" ); document.write( "\"N+=+2D%2B7\" so we'll substitute the N with 2D+7 to get:
\n" ); document.write( "\"%282D%2B7%29%2FD+\" and the reciprocal of this is 0.4, so...
\n" ); document.write( "\"D%2F%282D%2B7%29+=+0.4\" Replace the 0.4 with its fractional equvalent of \"4%2F10\"
\n" ); document.write( "\"D%2F%282D%2B7%29+=+4%2F10\" Now cross-multiply.
\n" ); document.write( "\"10D+=+4%282D%2B7%29\" Simplify and solve for D.
\n" ); document.write( "\"10D+=+8D%2B28\" Subtract 8D from both sides.
\n" ); document.write( "\"2D+=+28\" Divide both sides by 2.
\n" ); document.write( "\"D+=+14\" and...
\n" ); document.write( "\"N+=+2D%2B7\"
\n" ); document.write( "\"N+=+2%2814%29%2B7\"
\n" ); document.write( "\"N+=+35\"
\n" ); document.write( "The original fraction is:
\n" ); document.write( "\"N%2FD+=+35%2F14\"
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