document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=120847>Question 120847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The numerator of a fraction is seven more than twice the denominator. The value of the reciprocal of the fraction is 0.4. Find the original fraction.\r<BR>\n" );
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document.write( "Could someone please help me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88643 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88643\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2x+7)/x=.4<BR>\n" );
document.write( "2x+7=.4x<BR>\n" );
document.write( "2x-.4x=-7<BR>\n" );
document.write( "1.6x=-7<BR>\n" );
document.write( "x=-7/1.6<BR>\n" );
document.write( "x=-4.375 answer.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "(2*-4.375+7)/-4.375=.4<BR>\n" );
document.write( "(-8.75+7)/-4.375=.4<BR>\n" );
document.write( "-1.75/-4.375=.4<BR>\n" );
document.write( ".4=.4<BR>\n" );
document.write( " </SPAN>\n" );
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