document.write( "Question 120849: In five years time a father will be three times as old as his son. Five years ago, the father was six times as old as his son. Find their present age. \n" ); document.write( "
Algebra.Com's Answer #88639 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let x=son's present age; x+5=son's age in five year's time; x-5=son's age five year's ago \n" ); document.write( "And let y=father's present age; y-5= father's age five years ago and y+5=father's age in five year's time\r \n" ); document.write( "\n" ); document.write( "Now we are told that:\r \n" ); document.write( "\n" ); document.write( "y+5=3(x+5) get rid of parens \n" ); document.write( "y+5=3x+15 subtract 5 from both sides \n" ); document.write( "y+5-5=3x+15-5 collect like terms \n" ); document.write( "y=3x+10-----------------------------------------eq1 \n" ); document.write( "and that: \n" ); document.write( "y-5=6(x-5) get rid of parens \n" ); document.write( "y-5=6x-30 add 5 to both sides \n" ); document.write( "y-5+5=6x-30+5 collect like terms\r \n" ); document.write( "\n" ); document.write( "y=6x-25------------------------------eq2\r \n" ); document.write( "\n" ); document.write( "Substitute y=3x+10 from eq1 into eq2:\r \n" ); document.write( "\n" ); document.write( "3x+10=6x-25 subtract 3x from and add 25 to both sides\r \n" ); document.write( "\n" ); document.write( "3x-3x+10+25=6x-3x-25+25 collect like terms\r \n" ); document.write( "\n" ); document.write( "35=3x divide both sides by 3 \n" ); document.write( "x=11 2/3 years-----------------present age of son \n" ); document.write( "substitute 11 2/3 for x into eq1:\r \n" ); document.write( "\n" ); document.write( "y=3*(11 2/3)+10 \n" ); document.write( "y=35+10=45 years---------------------present age of father \n" ); document.write( "CK \n" ); document.write( "y+5=3(x+5) \n" ); document.write( "45+5=3*(11 2/3)+15 \n" ); document.write( "50=50 \n" ); document.write( "and \n" ); document.write( "y-5=6(x-5) \n" ); document.write( "45-5=6*(11 2/3)-30 \n" ); document.write( "40=70-30 \n" ); document.write( "40=40\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |