document.write( "Question 120721: Solve for:\r
\n" ); document.write( "\n" ); document.write( "a)\"+%28squareroot+of+2+%5E+%28squareroot+of+x%29%29+=+%28squareroot+of+2%5Ex%29++\"
\n" ); document.write( "b) \"+2+%5Ex%5E2+=+%282%5Ex%29%5E2\"
\n" ); document.write( "c) \"+2+%5E%28x%2B3%29+=+2+%5Ex+%2B3\"
\n" ); document.write( "d) \"+log%283x%29+=+3+log+x+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Thank you so much! :)
\n" ); document.write( "

Algebra.Com's Answer #88631 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
I'll do b, c, and d. Your rendering for part a is ambiguous. Do you mean \"sqrt%282%29%5Esqrt%28x%29=sqrt%282%5Ex%29\" or \"sqrt%282%5Esqrt%28x%29%29=sqrt%282%5Ex%29\"?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "b.) \"2+%5Ex%5E2+=+%282%5Ex%29%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Take the base-2 log of both sides:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"log%282%2C2%5Ex%5E2%29=log%282%2C%282%5Ex%29%5E2%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Remembering that \"log%28b%2Cx%5En%29=n%2Alog%28b%2Cx%29\" we can say:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Alog%282%2C2%29=2%2Alog%282%2C%282%5Ex%29%29\" and then apply the rule again to say:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Alog%282%2C2%29=2x%2Alog%282%2C%282%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now remember that \"log%28b%2Cb%29=1\" we can simplify to:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2=2x\", or\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "c. \"2+%5E%28x%2B3%29+=+2+%5Ex+%2B3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Remember that \"b%5E%28a%2Bc%29=b%5Ea%2Ab%5Ec\", so:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%5Ex%2A2%5E3=2%5Ex%2B3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Add \"-2%5Ex\" to both sides:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%5Ex%2A2%5E3-2%5Ex=3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Factor out \"2%5Ex\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%282%5Ex%29%282%5E3-1%29=3\"
\n" ); document.write( "\"%282%5Ex%29%288-1%29=3\"
\n" ); document.write( "\"%282%5Ex%29%287%29=3\"
\n" ); document.write( "\"2%5Ex=3%2F7\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Take the log base 2 of both sides:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"log%282%2C2%5Ex%29=log%282%2C3%2F7%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Again, using \"log%28b%2Cx%5En%29=n%2Alog%28b%2Cx%29\" we can say:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2Alog%282%2C2%29=log%282%2C3%2F7%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=log%282%2C3%2F7%29\" or \"x=log%282%2C3%29-log%282%2C7%29\" if you prefer.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "d. \"log%283x%29+=+3log%28x%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Using \"log%28b%2Cx%5En%29=n%2Alog%28b%2Cx%29\" in reverse we can say:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"log%283x%29+=+log%28x%5E3%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Take the antilog of both sides:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x=x%5E3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2=3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=sqrt%283%29\" Only the positive square root will do because the domain of the \"log%28b%2Cx%29\" function is constrained to \"0%3Cx%3C%2Binfinity\"
\n" ); document.write( "
\n" );