document.write( "Question 120842: Five years ago, Liz was twice as old as her younger sister. Five years from now, Liz will only be 1 1/3 times as old as her sister. How old is each now?\r
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document.write( "I'm really confused could someone help me please? \n" );
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Algebra.Com's Answer #88625 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Five years ago, Liz was twice as old as her younger sister. Five years from now, Liz will only be 1 1/3 times as old as her sister. How old is each now? \n" ); document.write( "-------------------- \n" ); document.write( "Five years ago DATA: \n" ); document.write( "Let sister be \"x\" yrs. old ; Liz was \"2x\" yrs. old \n" ); document.write( "-------------- \n" ); document.write( "Ages NOW DATA: \n" ); document.write( "Sister is x+5 yrs. old ; Liz is \"2x+5\" yrs. old. \n" ); document.write( "---------------- \n" ); document.write( "Five years from NOW DATA \n" ); document.write( "Sis will be x+10 yrs old ; Liz will be 2x+10 yrs old \n" ); document.write( "----------------- \n" ); document.write( "EQUATION: \n" ); document.write( "Five years from now, Liz will only be 1 1/3 times as old as her sister. \n" ); document.write( "2x+10 = (4/3)(x+10) \n" ); document.write( "2x-(4/3)x = (40/3)-10 \n" ); document.write( "(2/3)x = 10/3 \n" ); document.write( "x = 5 (Sis age NOW) \n" ); document.write( "2x = 10 (Liz age NOW) \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |