document.write( "Question 120677: A coffee merchant has coffee beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture? \n" ); document.write( "
Algebra.Com's Answer #88580 by ankor@dixie-net.com(22740)\"\" \"About 
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A coffee merchant has coffee beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture?
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\n" ); document.write( "Let x = amt of $12 coffee required
\n" ); document.write( "It said that a total of 100lb is required, therefore
\n" ); document.write( "Let (100-x) = amt of $9 coffee required
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\n" ); document.write( "12x + 9(100-x) = 11.25(100)
\n" ); document.write( "12x + 900x - 9x = 1125
\n" ); document.write( "12x - 9x = 1125 - 900
\n" ); document.write( "3x = 225
\n" ); document.write( "x = 225/3
\n" ); document.write( "x = 75 lb of $12 coffee, obviously that leaves 25 lb of $9 coffee required
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\n" ); document.write( "Check solution in original equation
\n" ); document.write( "12(75) + 9(25) = 1125
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\n" ); document.write( "Not that hard, right?
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