document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=120777>Question 120777</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Debbie has 80 metres of fencing to make a rectangular dog pound of dimensions length ,L,and width, W. What is the equation of the area of the dog pound as a function of length? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88553 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88553\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2W + 2L = 80, so divide both sides by 2:<BR>\n" );
document.write( "W+L = 40<BR>\n" );
document.write( "W= 40-L\r<BR>\n" );
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document.write( "Area = LW<BR>\n" );
document.write( "Area = L(40-L)<BR>\n" );
document.write( "Area = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=40L+-L%5E2 ALIGN=MIDDLE  ALT=\"40L+-L%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "R^2 </SPAN>\n" );
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