document.write( "Question 120624: 2x+y=9
\n" ); document.write( "-3x+2y=4
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Algebra.Com's Answer #88524 by nabla(475)\"\" \"About 
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Solve the first equation for y:
\n" ); document.write( "\"y=-2x%2B9\"
\n" ); document.write( "Substitute this y into the second equation:
\n" ); document.write( "\"-3x%2B2%28-2x%2B9%29=4\"
\n" ); document.write( "\"-7x=-14\" Combine terms on the left, subtract 19 from both sides
\n" ); document.write( "\"x=2\" Divide both sides by -7.\r
\n" ); document.write( "\n" ); document.write( "Now, substitute this value of x into the first equation where we solved for y in terms of x: \"y=-2%282%29%2B9=-4%2B9=5\".\r
\n" ); document.write( "\n" ); document.write( "This gives the solution set S:{2,5}.\r
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\n" ); document.write( "\n" ); document.write( "Additionally, we could solve this system through techniques of linear algebra as follows:
\n" ); document.write( "Matrix:
\n" ); document.write( "|2 1 9|
\n" ); document.write( "|-3 2 4|\r
\n" ); document.write( "\n" ); document.write( "(3/2)R1+R2->
\n" ); document.write( "|2 1 9|
\n" ); document.write( "|0 7/2 35/2|\r
\n" ); document.write( "\n" ); document.write( "(1/2)R1->
\n" ); document.write( "|1 1/2 9/2|
\n" ); document.write( "|0 7/2 35/2|\r
\n" ); document.write( "\n" ); document.write( "(2/7)R2->
\n" ); document.write( "|1 1/2 9/2|
\n" ); document.write( "|0 1 5 |\r
\n" ); document.write( "\n" ); document.write( "-1/2R2+R1->
\n" ); document.write( "|1 0 2 |
\n" ); document.write( "|0 1 5 |\r
\n" ); document.write( "\n" ); document.write( "Making S={2,5} the only solution.
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