document.write( "Question 120264: Question:
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document.write( "James paddled his boat upstream for one mile. He continued for
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document.write( "another 15 minutes, then turned around and paddled downstream,
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document.write( "arriving at his starting point in exactly 1 hour.How fast is the
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document.write( "current of the stream? \n" );
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Algebra.Com's Answer #88495 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! James paddled his boat upstream for one mile. He continued for \n" ); document.write( "another 15 minutes, then turned around and paddled downstream, \n" ); document.write( "arriving at his starting point in exactly 1 hour.How fast is the \n" ); document.write( "current of the stream? \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "I am not real happy with what I came up with, but here it is: \n" ); document.write( ": \n" ); document.write( "Going over what you had: \n" ); document.write( "Solution:This is what i did,I defined 2 variables \n" ); document.write( "B = speed of boat in still water, in miles per hour \n" ); document.write( "C = speed of current, in miles per hour\r \n" ); document.write( "\n" ); document.write( "Distance Rate Time \n" ); document.write( "Upstream 1 mile + 1/4hr(B-C) B-C 1/4hr<<<< \n" ); document.write( "The problem here is we don't know total time of the upstream trip at this point \n" ); document.write( ": \n" ); document.write( "The distance both ways can be written as (1+.25(B-C)) \n" ); document.write( ": \n" ); document.write( "On the return trip, this distance was covered in 1 hr so we can also say: \n" ); document.write( " (1+.25(B-C)) mph, the speed can also be written (B+C)mph \n" ); document.write( ": \n" ); document.write( "A Speed equation: \n" ); document.write( "(1+.25(B-C)) = (B+C) \n" ); document.write( "1 + .25B - .25C = B + C \n" ); document.write( "1 +.25B - B - .25C - C = 0 \n" ); document.write( "-.75B - 1.25C = -1 \n" ); document.write( "or mult by -1 \n" ); document.write( ".75B + 1.25C = +1 \n" ); document.write( "Get rid of the decimals, multiply by 4 \n" ); document.write( "3B + 5C = 4 \n" ); document.write( ": \n" ); document.write( "But we have only 1 equation and two unknowns. I have been unable to generate \n" ); document.write( "another equation from the information given. \n" ); document.write( ": \n" ); document.write( "Taking the above equation and graphing it, where y is the speed in still water, \n" ); document.write( " and x is the speed of the current: \n" ); document.write( "3y + 5x = 4 \n" ); document.write( "3y = -5x + 4 \n" ); document.write( "y = \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "You can see the positive values are very limited, \n" ); document.write( ": \n" ); document.write( "If you had a still water speed of 1 mph, the current would be .2 mph. \n" ); document.write( "this would work in our problem, B=1; C=.2 \n" ); document.write( ": \n" ); document.write( "Distance 1 + .25(1-.2) = 1 + .25(.8) = 1.2 mi is the distance \n" ); document.write( ": \n" ); document.write( "The downstream speed 1 + .2 = 1.2 mph and of course to cover 1.2 mi would be 1 hr \n" ); document.write( "This would be the only still water speed that is an integer \n" ); document.write( ": \n" ); document.write( "As I said I am not real happy with it. \n" ); document.write( " |