document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=18453>Question 18453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Show that for s (semiperimeter), r(radius of inscribed circle), and R (radius of circumscribed circle), abc = 4srR.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8846 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we got area of a triangle =(1/2)b*c* Sin A = r*s<BR>\n" );
document.write( "we also have the formula that a/Sin A=2R..or...Sin A =a/2R..using this we get <BR>\n" );
document.write( "(1/2)b*c* Sin A = (1/2)*b*c*a/2R=a*b*c/4R = r*s...or a*b*c=4R*r*s\r<BR>\n" );
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