document.write( "Question 120650: Solve the following system by addition. If a unique solution does not exist, state whether the system is inconsistent or dependent:\r
\n" ); document.write( "\n" ); document.write( "2x+3y=1
\n" ); document.write( "5x+3y=16
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Algebra.Com's Answer #88455 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"2%2Ax%2B3%2Ay=1\"
\n" ); document.write( " \"5%2Ax%2B3%2Ay=16\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 2 and 5 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 2 and 5 is 10, we need to multiply both sides of the top equation by 5 and multiply both sides of the bottom equation by -2 like this:
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\n" ); document.write( " \"5%2A%282%2Ax%2B3%2Ay%29=%281%29%2A5\" Multiply the top equation (both sides) by 5
\n" ); document.write( " \"-2%2A%285%2Ax%2B3%2Ay%29=%2816%29%2A-2\" Multiply the bottom equation (both sides) by -2
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"10%2Ax%2B15%2Ay=5\"
\n" ); document.write( " \"-10%2Ax-6%2Ay=-32\"
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\n" ); document.write( " Notice how 10 and -10 add to zero (ie \"10%2B-10=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%2810%2Ax-10%2Ax%29%2B%2815%2Ay-6%2Ay%29=5-32\"
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\n" ); document.write( " \"%2810-10%29%2Ax%2B%2815-6%29y=5-32\"
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\n" ); document.write( " \"cross%2810%2B-10%29%2Ax%2B%2815-6%29%2Ay=5-32\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"9%2Ay=-27\"
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\n" ); document.write( " \"y=-27%2F9\" Divide both sides by \"9\" to solve for y
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\n" ); document.write( " \"y=-3\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"2%2Ax%2B3%2Ay=1\" to solve for x
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\n" ); document.write( " \"2%2Ax%2B3%28-3%29=1\" Plug in \"y=-3\"
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\n" ); document.write( " \"2%2Ax-9=1\" Multiply
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\n" ); document.write( " \"2%2Ax=1%2B9\" Subtract \"-9\" from both sides
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\n" ); document.write( " \"2%2Ax=10\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F2%29%282%29%29%2Ax=%2810%29%281%2F2%29\" Multiply both sides by \"1%2F2\". This will cancel out \"2\" on the left side.
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\n" ); document.write( " \"x=5\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=5\", \"y=-3\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"5\", \"-3\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"2%2Ax%2B3%2Ay=1\"
\n" ); document.write( " \"5%2Ax%2B3%2Ay=16\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"2%2Ax%2B3%2Ay=1\" (red) \"5%2Ax%2B3%2Ay=16\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"5\",\"-3\"). This verifies our answer.
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