document.write( "Question 120659: solve each systems of equations algebraically
\n" ); document.write( " 28. {2x+4y=10}
\n" ); document.write( " {3x-4y=-15}
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Algebra.Com's Answer #88443 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a linear system of equations by subsitution

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"2%2Ax%2B4%2Ay=10\"
\n" ); document.write( " \"3%2Ax-4%2Ay=-15\"
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\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
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\n" ); document.write( " Solve for y for the first equation
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\n" ); document.write( " \"4%2Ay=10-2%2Ax\"Subtract \"2%2Ax\" from both sides
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\n" ); document.write( " \"y=%2810-2%2Ax%29%2F4\" Divide both sides by 4.
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\n" ); document.write( " Which breaks down and reduces to
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\n" ); document.write( " \"y=5%2F2-%281%2F2%29%2Ax\" Now we've fully isolated y
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\n" ); document.write( " Since y equals \"5%2F2-%281%2F2%29%2Ax\" we can substitute the expression \"5%2F2-%281%2F2%29%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
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\n" ); document.write( " \"3%2Ax%2B-4%2Ahighlight%28%285%2F2-%281%2F2%29%2Ax%29%29=-15\" Replace y with \"5%2F2-%281%2F2%29%2Ax\". Since this eliminates y, we can now solve for x.
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\n" ); document.write( " \"3%2Ax-4%2A%285%2F2%29-4%28-1%2F2%29x=-15\" Distribute -4 to \"5%2F2-%281%2F2%29%2Ax\"
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\n" ); document.write( " \"3%2Ax-20%2F2%2B%284%2F2%29%2Ax=-15\" Multiply
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\n" ); document.write( " \"3%2Ax-10%2B2%2Ax=-15\" Reduce any fractions
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\n" ); document.write( " \"3%2Ax%2B2%2Ax=-15%2B10\"Add \"10\" to both sides
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\n" ); document.write( " \"3%2Ax%2B2%2Ax=-5\" Combine the terms on the right side
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\n" ); document.write( " \"5%2Ax=-5\" Now combine the terms on the left side.
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\n" ); document.write( " \"cross%28%281%2F5%29%285%2F1%29%29x=%28-5%2F1%29%281%2F5%29\" Multiply both sides by \"1%2F5\". This will cancel out \"5%2F1\" and isolate x
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\n" ); document.write( " So when we multiply \"-5%2F1\" and \"1%2F5\" (and simplify) we get
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\n" ); document.write( " \"x=-1\" <---------------------------------One answer
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\n" ); document.write( " Now that we know that \"x=-1\", lets substitute that in for x to solve for y
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\n" ); document.write( " \"3%28-1%29-4%2Ay=-15\" Plug in \"x=-1\" into the 2nd equation
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\n" ); document.write( " \"-3-4%2Ay=-15\" Multiply
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\n" ); document.write( " \"-4%2Ay=-15%2B3\"Add \"3\" to both sides
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\n" ); document.write( " \"-4%2Ay=-12\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F-4%29%28-4%29%29%2Ay=%28-12%2F1%29%281%2F-4%29\" Multiply both sides by \"1%2F-4\". This will cancel out -4 on the left side.
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\n" ); document.write( " \"y=-12%2F-4\" Multiply the terms on the right side
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\n" ); document.write( " \"y=3\" Reduce
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\n" ); document.write( " So this is the other answer
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\n" ); document.write( " \"y=3\"<---------------------------------Other answer
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\n" ); document.write( " So our solution is
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\n" ); document.write( " \"x=-1\" and \"y=3\"
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\n" ); document.write( " which can also look like
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\n" ); document.write( " (\"-1\",\"3\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"2%2Ax%2B4%2Ay=10\"
\n" ); document.write( " \"3%2Ax-4%2Ay=-15\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"2%2Ax%2B4%2Ay=10\" (red) and \"3%2Ax-4%2Ay=-15\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
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\n" ); document.write( " and we can see that the two equations intersect at (\"-1\",\"3\"). This verifies our answer.
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\n" ); document.write( " Plug in (\"-1\",\"3\") into the system of equations
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\n" ); document.write( " Let \"x=-1\" and \"y=3\". Now plug those values into the equation \"2%2Ax%2B4%2Ay=10\"
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\n" ); document.write( " \"2%2A%28-1%29%2B4%2A%283%29=10\" Plug in \"x=-1\" and \"y=3\"
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\n" ); document.write( " \"-2%2B12=10\" Multiply
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\n" ); document.write( " \"10=10\" Add
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\n" ); document.write( " \"10=10\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"-1\",\"3\") satisfies \"2%2Ax%2B4%2Ay=10\"
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\n" ); document.write( " Let \"x=-1\" and \"y=3\". Now plug those values into the equation \"3%2Ax-4%2Ay=-15\"
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\n" ); document.write( " \"3%2A%28-1%29-4%2A%283%29=-15\" Plug in \"x=-1\" and \"y=3\"
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\n" ); document.write( " \"-3-12=-15\" Multiply
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\n" ); document.write( " \"-15=-15\" Add
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\n" ); document.write( " \"-15=-15\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"-1\",\"3\") satisfies \"3%2Ax-4%2Ay=-15\"
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\n" ); document.write( " Since the solution (\"-1\",\"3\") satisfies the system of equations
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\n" ); document.write( " \"2%2Ax%2B4%2Ay=10\"
\n" ); document.write( " \"3%2Ax-4%2Ay=-15\"
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\n" ); document.write( " this verifies our answer.
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