document.write( "Question 120632This question is from textbook Algebra Structure and Method
\n" ); document.write( ": I have been trying for two hours to get this, but I can't. Can someone PLEASE help???\r
\n" ); document.write( "\n" ); document.write( "A car and a bike set out at noon from the same point headed in the same direction. At 1:00 P.M., the car is 60 km ahead of the bike. Find how fast each travels, given that the car travels four times as fast as the bike.
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Algebra.Com's Answer #88442 by josmiceli(19441)\"\" \"About 
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I need to use \"d+=+r%2At\". There is a separate equation for
\n" ); document.write( "bike and car
\n" ); document.write( "\"d%5Bb%5D+=+r%5Bb%5D%2At%5Bb%5D\"
\n" ); document.write( "\"d%5Bc%5D+=+r%5Bc%5D%2At%5Bc%5D\"
\n" ); document.write( "Call the distance the car travels \"d%5Bb%5D+%2B+60\" km
\n" ); document.write( "Then the distance the bike travels is \"d%5Bb%5D\" km
\n" ); document.write( "Given: \"r%5Bc%5D+=+4%2Ar%5Bb%5D\"
\n" ); document.write( "We are starting a stopwatch at noon and stopping it at 1:00 PM, so
\n" ); document.write( "\"t%5Bb%5D+=+1\" hr
\n" ); document.write( "\"t%5Bc%5D+=+1\" hr
\n" ); document.write( "\"d%5Bb%5D+=+r%5Bb%5D%2A1\"
\n" ); document.write( "\"d%5Bb%5D+%2B+60+=+4%2Ar%5Bb%5D%2A1\"
\n" ); document.write( "substitute \"r%5Bb%5D%2A1\" for \"d%5Bb%5D\" in the 2nd equation
\n" ); document.write( "\"r%5Bb%5D+%2B+60+=+4%2Ar%5Bb%5D\"
\n" ); document.write( "\"3%2Ar%5Bb%5D+=+60\"
\n" ); document.write( "\"r%5Bb%5D+=+20\" km/hr answer
\n" ); document.write( "\"r%5Bc%5D+=+4%2A20\"
\n" ); document.write( "\"r%5Bc%5D+=+80\" km/hr answer
\n" ); document.write( "check
\n" ); document.write( "\"d%5Bb%5D+=+r%5Bb%5D%2At%5Bb%5D\"
\n" ); document.write( "\"d%5Bc%5D+=+r%5Bc%5D%2At%5Bc%5D\"
\n" ); document.write( "----------------------
\n" ); document.write( "\"d%5Bb%5D+=+20%2A1\"
\n" ); document.write( "\"d%5Bc%5D+=+80%2A1\"
\n" ); document.write( "The difference is 60 km
\n" ); document.write( "OK
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