document.write( "Question 120599This question is from textbook algebra: structure and Method: book 1
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document.write( ": i need help with this problem!! The ratio of Alex's cycling speed to Bart's cycling speed is 6:5. Bart leaves school at 3:00 pm and alex leaves at 3:10 pm. By 3:30, Alex is only 2 km behind Bart. How fast is each boy going? PLEASE HELP!!! I AM SORRY IF THIS ISN'T ENOUGH INFO, BUT THAT IS ALL THAT IS IN THE BOOK!!!!!! \n" );
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Algebra.Com's Answer #88430 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The ratio of Alex's cycling speed to Bart's cycling speed is 6:5. Bart leaves school at 3:00 pm and Alex leaves at 3:10 pm. By 3:30, Alex is only 2 km behind Bart. How fast is each boy going? \n" ); document.write( ": \n" ); document.write( "What we know here: \n" ); document.write( "At 3:30: \n" ); document.write( "B's traveling time = 30 min or \n" ); document.write( "A's traveling time = 20 min or \n" ); document.write( ": \n" ); document.write( "If A's speed = x \n" ); document.write( "Then B's speed = \n" ); document.write( ": \n" ); document.write( "Write a distance equation: Distance = time * speed \n" ); document.write( ": \n" ); document.write( "B's dist - A's dist = 2 km \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by 12 to get rid of the denominators \n" ); document.write( "12* \n" ); document.write( ": \n" ); document.write( "Cancel out the denominators and you have: \n" ); document.write( ": \n" ); document.write( "5x - 4x = 24 \n" ); document.write( "x = 24 km/hr is A's speed \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check their distances from the start at 3:30: \n" ); document.write( "B travels \n" ); document.write( "A travels |