document.write( "Question 120615: x=3y+1
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Algebra.Com's Answer #88429 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Start with the given system\r
\n" ); document.write( "\n" ); document.write( "\"2x-4y=-2\"
\n" ); document.write( "\"x=3y%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%283y%2B1%29-4y=-2\" Plug in \"x=3y%2B1\" into the first equation. In other words, replace each \"x\" with \"3y%2B1\". Notice we've eliminated the \"x\" variables. So we now have a simple equation with one unknown.\r
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\n" ); document.write( "\n" ); document.write( "\"6y%2B2-4y=-2\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"2y%2B2=-2\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"2y=-2-2\"Subtract 2 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2y=-4\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-4%29%2F%282%29\" Divide both sides by 2 to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=-2\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Now that we know that \"y=-2\", we can plug this into \"x=3y%2B1\" to find \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=3%28-2%29%2B1\" Substitute \"-2\" for each \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-5\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x=-5\" and \"y=-2\" which also looks like \r
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