document.write( "Question 120588: How would I graph the following equations: (a) y = 1/3x + 1 (b) y = -3x + 1 (c) y = 3x + 1 (d) y = -1/3x + 1? \n" ); document.write( "
Algebra.Com's Answer #88415 by solver91311(24713)\"\" \"About 
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Use the same procedure to graph any linear equation. I'll do one of them.\r
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\n" ); document.write( "\n" ); document.write( "Select two values for x. It doesn't really matter which values you select, but I like small, easy to manipulate numbers like 0 and 1. Since these are linear equations, i.e. you get a straight line when you graph them, you only need to determine two points.\r
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\n" ); document.write( "\n" ); document.write( "Once you have chosen your x values, evaluate the equation for each by substituting each of your chosen values for x and solving for y.\r
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\n" ); document.write( "\n" ); document.write( "In your first problem, let x = 0. \"y=%281%2F3%29%280%29%2B1=1\". So if x is 0, y is 1, and one of the points on our line is (0,1). Now let x = 3. (I chose three because 3 is the denominator of the coefficient fraction) \"y=%281%2F3%29%283%29%2B1=1%2B1=2\". So if x is 3, y is 2, and another point on our line is (3,2).\r
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\n" ); document.write( "\n" ); document.write( "Plot these two points on your graph. I've labeled them A and B\r
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\n" ); document.write( "\n" ); document.write( "Now construct a straight line through the two points with a straight edge and you are done.\r
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\n" ); document.write( "\n" ); document.write( "All you have to do is follow the same procedure for each of the other three problems.\r
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