document.write( "Question 120595: An investment of $1500 paid interest of $45 during a certain period.How much interest would an investment of $2000 invested at the same rate for the same length of time pay? \n" ); document.write( "
Algebra.Com's Answer #88408 by checkley71(8403) ![]() You can put this solution on YOUR website! 45/1500=X/2000 CROSS MULTIPLY \n" ); document.write( "1500X=45*2000 \n" ); document.write( "1500X=90,000 \n" ); document.write( "X=90,000/1500 \n" ); document.write( "X=60 ANSWER FOR THE AMOUNT OF INTEREST ON THE 2000 INVESTMENT. \n" ); document.write( " |