document.write( "Question 120595: An investment of $1500 paid interest of $45 during a certain period.How much interest would an investment of $2000 invested at the same rate for the same length of time pay? \n" ); document.write( "
Algebra.Com's Answer #88408 by checkley71(8403)\"\" \"About 
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45/1500=X/2000 CROSS MULTIPLY
\n" ); document.write( "1500X=45*2000
\n" ); document.write( "1500X=90,000
\n" ); document.write( "X=90,000/1500
\n" ); document.write( "X=60 ANSWER FOR THE AMOUNT OF INTEREST ON THE 2000 INVESTMENT.
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