document.write( "Question 120556: The length of a rectangle is 20cm greater than its width. The perimeter is 360cm. What is the area?\r
\n" ); document.write( "\n" ); document.write( "I really don't understand this, could someone please help?
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Algebra.Com's Answer #88383 by tutor_paul(519)\"\" \"About 
You can put this solution on YOUR website!
The perimeter (P) of a rectangle is:
\n" ); document.write( "\"P=2l%2B2w\" where l=length and w=width.
\n" ); document.write( "Based on the information given, we can use this equation to determine the sides of the rectangle, and from that, we can get the area.
\n" ); document.write( "Re-write the Perimeter equation based on the information given:
\n" ); document.write( "\"360=2%28w%2B20%29%2B2w\"
\n" ); document.write( "Solve for w:
\n" ); document.write( "\"360=2w%2B40%2B2w\"
\n" ); document.write( "\"4w=320\"
\n" ); document.write( "\"w=80\"
\n" ); document.write( "Now that you have w, you can easily find l:
\n" ); document.write( "\"l=w%2B20\"
\n" ); document.write( "\"l=80%2B20\"
\n" ); document.write( "\"l=100\"
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\n" ); document.write( "So now you have the length and the width - this is what you need to find the area, since the equation for the area of a rectangle is:
\n" ); document.write( "\"A=l%2Aw\"
\n" ); document.write( "Substituting in:
\n" ); document.write( "\"A=100%2A80\"
\n" ); document.write( "\"highlight%28A=8000%29\" cm^2
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\n" ); document.write( "Good Luck,
\n" ); document.write( "tutor_paul@yahoo.com
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