document.write( "Question 120519: A plane flies 720 mi against a steady 30-mi/h headwind and then returns to the same point with the wind. If the entire trip takes 10 h, what is the plane’s speed in still air? \n" ); document.write( "
Algebra.Com's Answer #88360 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Let r be the speed in still air, in accordance with rule one for word problems: Set the variable equal to the thing you want to know.\r
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\n" ); document.write( "\n" ); document.write( "Air speed against the wind would then be \"r-30\" and airspeed with the wind would be \"r%2B30\". If the against the wind part of the trip takes t hours, then the return trip must take 10 - t hours, because the entire trip took 10 hours.\r
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\n" ); document.write( "\n" ); document.write( "The formula for straight-line distance in terms of constant rate over a period of time is \"d=rt\". So we can express time as a function of distance and rate by saying \"t=d%2Fr\".\r
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\n" ); document.write( "\n" ); document.write( "In our case, the time for the outbound trip, t, is given by \"t=720%2F%28r-30%29\". The time for the return trip, 10 - t, is given by \"10-t=720%2F%28r%2B30%29\"\r
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\n" ); document.write( "\n" ); document.write( "First solve this second equation for t:\r
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\n" ); document.write( "\n" ); document.write( "\"-t=%28720%2F%28r%2B30%29%29-10\"\r
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\n" ); document.write( "\n" ); document.write( "\"t=10-%28720%2F%28r%2B30%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t=%2810%28r%2B30%29-720%29%2F%28r%2B30%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t=%2810r%2B300-720%29%2F%28r%2B30%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t=%2810r-420%29%2F%28r%2B30%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now, note that we have two expressions for t in terms of r. Set them equal to each other:\r
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\n" ); document.write( "\n" ); document.write( "\"720%2F%28r-30%29=%2810r-420%29%2F%28r%2B30%29\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply by \"%28r%2B30%29%28r-30%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"720%28r%2B30%29=%2810r-420%29%28r-30%29\"\r
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\n" ); document.write( "\n" ); document.write( "Distribute and collect terms\r
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\n" ); document.write( "\n" ); document.write( "\"720r%2B21600=10r%5E2-300r-420r%2B12600\"
\n" ); document.write( "\"10r%5E2-1440r-9000=0\"\r
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\n" ); document.write( "\n" ); document.write( "Divide by 10\r
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\n" ); document.write( "\n" ); document.write( "\"r%5E2-144r-900=0\"\r
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\n" ); document.write( "\n" ); document.write( "Note that \"-150%2A6=-900\" and \"-150%2B6=-144\", so\r
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\n" ); document.write( "\n" ); document.write( "\"%28r-150%29%28r%2B6%29=0\" => \"r=150\" or \"r=-6\"\r
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\n" ); document.write( "\n" ); document.write( "The solution set to the quadratic is therefore 150 or -6. Since flying backwards doesn't make much sense, exclude the -6 value as an extraneous root. The speed in still air is 150 miles per hour.\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"720%2F%28150-30%29=720%2F120=6\" and \"720%2F%28150%2B30%29=720%2F180=4\", and finally, 6 + 4 = 10. Answer checks.\r
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\n" ); document.write( "\n" ); document.write( "Hope that helps,
\n" ); document.write( "John
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