document.write( "Question 120519: A plane flies 720 mi against a steady 30-mi/h headwind and then returns to the same point with the wind. If the entire trip takes 10 h, what is the plane’s speed in still air? \n" ); document.write( "
Algebra.Com's Answer #88339 by stanbon(75887)\"\" \"About 
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A plane flies 720 miles against a steady 30 mph headwind and then returns to the same point with the wind, if the entire trip takes 10 hours what is the plane's speed in still air?
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\n" ); document.write( "Let \"p\" be the plane's speed in still air.
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\n" ); document.write( "Upwind DATA;
\n" ); document.write( "Distance = 720 miles ; Rate = p-30; time = d/r = 720/(p-30) hrs.
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\n" ); document.write( "Downwind DATa:
\n" ); document.write( "Distance = 720 miles ; Rate = p+30: time = d/r = 720/(p+30) hrs
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\n" ); document.write( "EQUATION:
\n" ); document.write( "time up + time down = 10 hrs
\n" ); document.write( "720/(p-30) + 720/(p+30) = 10
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\n" ); document.write( "Divide thru by 10 to get:
\n" ); document.write( "72/(p-30) + 72/(p+30) = 1
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\n" ); document.write( "Multiply thru by (p-30)(p+30)=p^2-900
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\n" ); document.write( "72(p+30) + 72(p-30) = p^2-900
\n" ); document.write( "144p = p^2-900
\n" ); document.write( "p^2-144p-900= 0
\n" ); document.write( "(p-150)(p+6) = 0
\n" ); document.write( "p = 150 mph (plane speed in still air is 150 mph)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \r
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