document.write( "Question 120492: The time in seconds it takes for an object to fall from rest is given by t = 1/4squared s, in which s is the distance fallen. What is the time it takes an object to fakk from a building 1400 feet high? I have tried 1/4 the distance fallen squared, and I just don't know how to figure this one out in seconds? \n" ); document.write( "
Algebra.Com's Answer #88322 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! Your formula is incorrect.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you drop an object from a fixed height, s, the height, h, of the object after t seconds is given by \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In general, if you drop an object from height s in feet and you want to know the time it takes to reach height h in feet, it takes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, if the heights are given in meters, then the constant factor is different:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope that helps \n" ); document.write( "John \n" ); document.write( " |