document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=120481>Question 120481</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A small area in front of a building is triangular in shape. The perimeter of \r<BR>\n" );
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document.write( "the triangle is 37 meters. The second side is one-half of the first side in length. The third side is 3 meters less than the first side. Find the length in meters of each side of the triangular region. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88306 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+x/2+x-3=37<BR>\n" );
document.write( "x+.5x+x=37+3<BR>\n" );
document.write( "2.5x=40<BR>\n" );
document.write( "x=40/2.5<BR>\n" );
document.write( "x=16 is the length of the first side.<BR>\n" );
document.write( "16/2=8 for the second side.<BR>\n" );
document.write( "16-3=13 for the third side.<BR>\n" );
document.write( "poof:<BR>\n" );
document.write( "16+8+13=37<BR>\n" );
document.write( "37=37 </SPAN>\n" );
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