document.write( "Question 120423: I don't fully understand area with squares and how many sides it has.This is a factoring word problem when you have to use the principle of zero. THe question says \"If the sides of a square are increased by 3 inches., the area becomes 64 inches^2. Find the length of a side of the original square.\" Could you please help me? \n" ); document.write( "
Algebra.Com's Answer #88261 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let x=side length of original square\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Remember the area of any square with side x is: \"A=x%2Ax=x%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now if the side length is increased by 3, then the new side becomes: \"x%2B3\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the new area becomes: \"A=%28x%2B3%29%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"A=%28x%2B3%29%5E2\" Start with the given equation\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"64=%28x%2B3%29%5E2\" Plug in A=64 (this is the area of the new square)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"64=x%5E2%2B6x%2B9\" Foil\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0=x%5E2%2B6x%2B9-64\" Subtract 64 from both sides\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0=x%5E2%2B6x-55\" Combine like terms\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x%2B11%29%28x-5%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"x%2B11=0\" or \"x-5=0\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=-11\" or \"x=5\" Now solve for x in each case\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So our answer is \r
\n" ); document.write( "\n" ); document.write( " \"x=-11\" or \"x=5\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "However, since a negative length doesn't make sense, our only solution is \"x=5\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the original side length is 5 inches\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );