document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=120413>Question 120413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THis is a factoring word problem using the principle of zero. The question says \"Find two consecutive, negative integers whose product is 156.\" Could you please help me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88250 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"Find two consecutive, negative integers whose product is 156.\" Could you please help me?<BR>\n" );
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document.write( "Let the 1st be \"x\"; the 2nd would be \"x+1\".<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "x(x+1) = 156<BR>\n" );
document.write( "x^2+x-156 = 0<BR>\n" );
document.write( "x = [-1 +- sqrt(1-4*1*-156)]/2<BR>\n" );
document.write( "x = [-1 +- sqrt(625)]/2<BR>\n" );
document.write( "x = [-1 +- 25]/2<BR>\n" );
document.write( "Negative soution:<BR>\n" );
document.write( "x = (-1-25)/2 = -13 (1st negative integer)<BR>\n" );
document.write( "x+1 = -12 (2nd negative integer)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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