document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=18357>Question 18357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two number is 105. one of the numbers decreased by 20 is equal to the other decreased by 15. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8824 by </B><A HREF=/tutors/aboutme.mpl?userid=piglet162431><B>piglet162431(90)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=piglet162431><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I came up with 50 and 55.<BR>\n" );
document.write( "First, write an equation for it.(They ALWAYS is better than guessing)<BR>\n" );
document.write( "let n be one of the numbers<BR>\n" );
document.write( "Since, if you subtract one number by 20= other by 15, it's obviously telling us that the difference between the two numbers is 5.<BR>\n" );
document.write( "So: (n)+(n-5)=105<BR>\n" );
document.write( "Simplify: 2n-5= 105<BR>\n" );
document.write( "2n=110<BR>\n" );
document.write( "n=55<BR>\n" );
document.write( "110-55= 50<BR>\n" );
document.write( "The two numbers are 50, and 55<BR>\n" );
document.write( "If you check, they'll work. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );