document.write( "Question 120355: find 3 consecutive integers so that twice the first is twelve more than the third. \n" ); document.write( "
Algebra.Com's Answer #88230 by Kalmetam(43)![]() ![]() ![]() You can put this solution on YOUR website! so we are finding:\r \n" ); document.write( "\n" ); document.write( "A,B,C\r \n" ); document.write( "\n" ); document.write( "and those are the numbers from least to greatest..\r \n" ); document.write( "\n" ); document.write( "and:\r \n" ); document.write( "\n" ); document.write( "2B=N \n" ); document.write( "C+12=N\r \n" ); document.write( "\n" ); document.write( "Lets start RANDOM!!\r \n" ); document.write( "\n" ); document.write( "lets say:\r \n" ); document.write( "\n" ); document.write( "1,2,3\r \n" ); document.write( "\n" ); document.write( "Then \r \n" ); document.write( "\n" ); document.write( "2*2=4 \n" ); document.write( "4=n\r \n" ); document.write( "\n" ); document.write( "C+12=n FALSE\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "Lets try a bit higher..\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "11,12,13 \n" ); document.write( "12*2=24 \n" ); document.write( "24=n \n" ); document.write( "13+12=24 WRONG\r \n" ); document.write( "\n" ); document.write( "---- \n" ); document.write( "That was extremely close \n" ); document.write( "lets try one number up and exclude the 11.. that should work since 24 is one number down.. \n" ); document.write( "---- \n" ); document.write( "12,13,14 \n" ); document.write( "13*2=26 \n" ); document.write( "14+12=26 TRUE \n" ); document.write( "--- \n" ); document.write( "The integers are: 12,13,14 \n" ); document.write( " |