document.write( "Question 120355: find 3 consecutive integers so that twice the first is twelve more than the third. \n" ); document.write( "
Algebra.Com's Answer #88230 by Kalmetam(43)\"\" \"About 
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so we are finding:\r
\n" ); document.write( "\n" ); document.write( "A,B,C\r
\n" ); document.write( "\n" ); document.write( "and those are the numbers from least to greatest..\r
\n" ); document.write( "\n" ); document.write( "and:\r
\n" ); document.write( "\n" ); document.write( "2B=N
\n" ); document.write( "C+12=N\r
\n" ); document.write( "\n" ); document.write( "Lets start RANDOM!!\r
\n" ); document.write( "\n" ); document.write( "lets say:\r
\n" ); document.write( "\n" ); document.write( "1,2,3\r
\n" ); document.write( "\n" ); document.write( "Then \r
\n" ); document.write( "\n" ); document.write( "2*2=4
\n" ); document.write( "4=n\r
\n" ); document.write( "\n" ); document.write( "C+12=n FALSE\r
\n" ); document.write( "\n" ); document.write( "---\r
\n" ); document.write( "\n" ); document.write( "Lets try a bit higher..\r
\n" ); document.write( "\n" ); document.write( "---\r
\n" ); document.write( "\n" ); document.write( "11,12,13
\n" ); document.write( "12*2=24
\n" ); document.write( "24=n
\n" ); document.write( "13+12=24 WRONG\r
\n" ); document.write( "\n" ); document.write( "----
\n" ); document.write( "That was extremely close
\n" ); document.write( "lets try one number up and exclude the 11.. that should work since 24 is one number down..
\n" ); document.write( "----
\n" ); document.write( "12,13,14
\n" ); document.write( "13*2=26
\n" ); document.write( "14+12=26 TRUE
\n" ); document.write( "---
\n" ); document.write( "The integers are: 12,13,14
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