document.write( "Question 120350: i dont kno0w how to sove for substitution elimination or graphing for this problem 2x-y=1 and 3x+y=-6 \n" ); document.write( "
Algebra.Com's Answer #88227 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Substitution:\r
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\n" ); document.write( "\n" ); document.write( "Eq. 1) \"2x-y=1\"
\n" ); document.write( "Eq. 2) \"3x%2By=-6\"\r
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\n" ); document.write( "\n" ); document.write( "Solve equation 1 for y:\r
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\n" ); document.write( "\n" ); document.write( "\"2x-y=1\"
\n" ); document.write( "\"-y=-2x%2B1\"
\n" ); document.write( "\"y=2x-1\"\r
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\n" ); document.write( "\n" ); document.write( "Take the expression just developed for y and substitute it into equation 2 in place of the y:\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2By=-6\"
\n" ); document.write( "\"3x%2B%282x-1%29=-6\"\r
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\n" ); document.write( "\n" ); document.write( "Now solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B%282x-1%29=-6\"
\n" ); document.write( "\"5x-1=-6\"
\n" ); document.write( "\"5x=-6%2B1\"
\n" ); document.write( "\"5x=-5\"
\n" ); document.write( "\"x=-1\"}\r
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\n" ); document.write( "\n" ); document.write( "Substitute this value for x into equation 1 and solve for y:\r
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\n" ); document.write( "\n" ); document.write( "\"2%28-1%29-y=1\"
\n" ); document.write( "\"-2-y=1\"
\n" ); document.write( "\"-y=1%2B2\"
\n" ); document.write( "\"y=-3\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore the solution set is the ordered pair (-1,-3)\r
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\n" ); document.write( "\n" ); document.write( "Elimination:\r
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\n" ); document.write( "\n" ); document.write( "Eq. 1) \"2x-y=1\"
\n" ); document.write( "Eq. 2) \"3x%2By=-6\"\r
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\n" ); document.write( "\n" ); document.write( "Add the two equations term-by-term:\r
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\n" ); document.write( "\n" ); document.write( "Sum: \"5x=-5\"\r
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\n" ); document.write( "\n" ); document.write( "Solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x=-1\"\r
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\n" ); document.write( "\n" ); document.write( "Since you have a -y in one equation and a y in the other, you can add the two equations directly to eliminate the y variable. In other problems where the coefficients are not direct additive inverses on one of the variables, you will have to multiply through one of the equations by an appropriate value to create the additive inverse situation.\r
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\n" ); document.write( "\n" ); document.write( "To illustrate the process, I'll solve for the y variable by elimination of the x variable:\r
\n" ); document.write( "\n" ); document.write( "\"2x-y=1\"
\n" ); document.write( "\"3x%2By=-6\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply equation 1 by 3, and equation 2 by -2:\r
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\n" ); document.write( "\n" ); document.write( "\"6x-3y=3\"
\n" ); document.write( "\"-6x-2y=12\"\r
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\n" ); document.write( "\n" ); document.write( "Now add the equations term by term:\r
\n" ); document.write( "\n" ); document.write( "Sum: \"-5y=15\"\r
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\n" ); document.write( "\n" ); document.write( "And solve for y:\r
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\n" ); document.write( "\n" ); document.write( "\"y=-3\"\r
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\n" ); document.write( "\n" ); document.write( "Again, the solution set is the ordered pair (-1,-3) (And I sincerely hope you aren't surprised that the two methods produce the same result. I wouldn't have been surprised necessarily if they had been different, but I would have been supremely confident that I had made an error in the performance of one or both of the methods.)\r
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\n" ); document.write( "\n" ); document.write( "Graphing:\r
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\n" ); document.write( "\n" ); document.write( "Select two x values for each of the lines, and then compute the corresponding y value for each selected x. This will give you two ordered pairs for each line. Plot the points and construct a straight line through each set of points. The solution will be where the two lines intersect.\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28400%2C400%2C-5%2C5%2C-5%2C5%2C2x-1%2C-3x-6%29\"\r
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\n" ); document.write( "\n" ); document.write( "And, as we suspected, the point of intersection is (-1,-3)\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps,
\n" ); document.write( "John\r
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