document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=120358>Question 120358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> mr c can type 66 words in 1.5 minutes. at the same rate how many words can he type in 3.5 minutes? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88226 by </B><A HREF=/tutors/aboutme.mpl?userid=Kalmetam><B>Kalmetam(43)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Kalmetam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> yeah let me try this in an easier way..\r<BR>\n" );
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document.write( "so he can type 66 in 1.5 minutes.. ok\r<BR>\n" );
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document.write( "Well if we add 2 to 1.5, we get 3.5, so we need to use a simple fraction of 1.5 that the denominator is a factor of 66, then we can multiply that to the amount needed to get 3.5\r<BR>\n" );
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document.write( "so lets see...\r<BR>\n" );
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document.write( "1/3 of 1.5 = x\r<BR>\n" );
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document.write( "Well 1/3 of 15 is 5, so this is .5\r<BR>\n" );
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document.write( "so..\r<BR>\n" );
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document.write( "x=.5\r<BR>\n" );
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document.write( "so lets see, we divided 1.5 by 3, now we need to divide 66 by 3.\r<BR>\n" );
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document.write( "66/3=y\r<BR>\n" );
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document.write( "so...\r<BR>\n" );
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document.write( "66/3=22\r<BR>\n" );
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document.write( "so now we have 22 words per 0.5 minutes.  <BR>\n" );
document.write( "now we need to know how many times that goes into 3.5\r<BR>\n" );
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document.write( "3.5/x=z<BR>\n" );
document.write( "3.5/.5=z<BR>\n" );
document.write( "z=7\r<BR>\n" );
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document.write( "and now you need to multiply the OTHER SIDE!\r<BR>\n" );
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document.write( "7y=u<BR>\n" );
document.write( "7*22=u<BR>\n" );
document.write( "u=154\r<BR>\n" );
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document.write( "he can type 154 words in 3.5 minutes.. <BR>\n" );
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