document.write( "Question 120349This question is from textbook Algebra 1
\n" ); document.write( ": Write the equation in slope-intercept form. Then graph the equation.\r
\n" ); document.write( "\n" ); document.write( "18. 3/2x + 3/2y = 3/4\r
\n" ); document.write( "\n" ); document.write( "The numbers with the slashes are fractions.\r
\n" ); document.write( "\n" ); document.write( "Thank you so much!
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Algebra.Com's Answer #88221 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Graphing Linear Equations

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\n" ); document.write( " \"%283%2F2%29%2Ax%2B%283%2F2%29%2Ay=3%2F4\"Start with the given equation
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\n" ); document.write( " \"%283%2F2%29%2Ay=3%2F4-%283%2F2%29%2Ax\" Subtract \"%283%2F2%29%2Ax\" from both sides
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\n" ); document.write( " \"y=%282%2F3%29%283%2F4-%283%2F2%29%2Ax%29\" Multiply both sides by \"2%2F3\"
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\n" ); document.write( " \"y=%282%2F3%29%283%2F4%29-%282%2F3%29%283%2F2%29x%29\" Distribute \"2%2F3\"
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\n" ); document.write( " \"y=6%2F12-%286%2F6%29x\" Multiply
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\n" ); document.write( " \"y=%28-6%2F6%29%2Ax%2B6%2F12\" Rearrange the terms
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\n" ); document.write( " \"y=-1%2Ax%2B1%2F2\" Reduce any fractions
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\n" ); document.write( " So the equation is now in slope-intercept form (\"y=mx%2Bb\") where \"m=-1\" (the slope) and \"b=1%2F2\" (the y-intercept)
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\n" ); document.write( " So to graph this equation lets plug in some points
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\n" ); document.write( " Plug in x=0
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\n" ); document.write( " \"y=-1%2A%280%29%2B1%2F2\"
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\n" ); document.write( " \"y=0%2B1%2F2\" Multiply
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\n" ); document.write( " \"y=1%2F2\" Add
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\n" ); document.write( " \"y=1%2F2\" Reduce
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\n" ); document.write( " So here's one point (0,0.5)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=1
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\n" ); document.write( " \"y=-1%2A%281%29%2B1%2F2\"
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\n" ); document.write( " \"y=-1%2B1%2F2\" Multiply
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\n" ); document.write( " \"y=-1%2F2\" Add
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\n" ); document.write( " \"y=-1%2F2\" Reduce
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\n" ); document.write( " So here's another point (1,-0.5). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=-1%2Ax%2B1%2F2\" through the points (0,0.5) and (1,-0.5)
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\n" ); document.write( " So from the graph we can see that the slope is \"-1%2F1\" (which tells us that in order to go from point to point we have to start at one point and go down -1 units and to the right 1 units to get to the next point), the y-intercept is (0,\"0.5\") ,or (0,\"1%2F2\"), and the x-intercept is (\"0.5\",0) ,or (\"1%2F2\",0) . So all of this information verifies our graph.
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\n" ); document.write( " We could graph this equation another way. Since \"b=1%2F2\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"1%2F2\").
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\n" ); document.write( " So we have one point (0,\"1%2F2\")
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\n" ); document.write( " Now since the slope is \"-1%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"1%2F2\"), we can go down 1 units
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\n" ); document.write( " and to the right 1 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=-1%2Ax%2B1%2F2\"
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\n" ); document.write( " So this is the graph of \"y=-1%2Ax%2B1%2F2\" through the points (0,0.5) and (1,-0.5)
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