document.write( "Question 120350: i dont kno0w how to sove for substitution elimination or graphing for this problem 2x-y=1 and 3x+y=-6 \n" ); document.write( "
Algebra.Com's Answer #88220 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a linear system of equations by subsitution

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"2%2Ax-1%2Ay=1\"
\n" ); document.write( " \"3%2Ax%2B1%2Ay=-6\"
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\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
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\n" ); document.write( " Solve for y for the first equation
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\n" ); document.write( " \"-1%2Ay=1-2%2Ax\"Subtract \"2%2Ax\" from both sides
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\n" ); document.write( " \"y=%281-2%2Ax%29%2F-1\" Divide both sides by -1.
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\n" ); document.write( " Which breaks down and reduces to
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\n" ); document.write( " \"y=-1%2B2%2Ax\" Now we've fully isolated y
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\n" ); document.write( " Since y equals \"-1%2B2%2Ax\" we can substitute the expression \"-1%2B2%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
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\n" ); document.write( " \"3%2Ax%2B1%2Ahighlight%28%28-1%2B2%2Ax%29%29=-6\" Replace y with \"-1%2B2%2Ax\". Since this eliminates y, we can now solve for x.
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\n" ); document.write( " \"3%2Ax%2B1%2A%28-1%29%2B1%282%29x=-6\" Distribute 1 to \"-1%2B2%2Ax\"
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\n" ); document.write( " \"3%2Ax-1%2B2%2Ax=-6\" Multiply
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\n" ); document.write( " \"3%2Ax-1%2B2%2Ax=-6\" Reduce any fractions
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\n" ); document.write( " \"3%2Ax%2B2%2Ax=-6%2B1\"Add \"1\" to both sides
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\n" ); document.write( " \"3%2Ax%2B2%2Ax=-5\" Combine the terms on the right side
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\n" ); document.write( " \"5%2Ax=-5\" Now combine the terms on the left side.
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\n" ); document.write( " \"cross%28%281%2F5%29%285%2F1%29%29x=%28-5%2F1%29%281%2F5%29\" Multiply both sides by \"1%2F5\". This will cancel out \"5%2F1\" and isolate x
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\n" ); document.write( " So when we multiply \"-5%2F1\" and \"1%2F5\" (and simplify) we get
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\n" ); document.write( " \"x=-1\" <---------------------------------One answer
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\n" ); document.write( " Now that we know that \"x=-1\", lets substitute that in for x to solve for y
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\n" ); document.write( " \"3%28-1%29%2B1%2Ay=-6\" Plug in \"x=-1\" into the 2nd equation
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\n" ); document.write( " \"-3%2B1%2Ay=-6\" Multiply
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\n" ); document.write( " \"1%2Ay=-6%2B3\"Add \"3\" to both sides
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\n" ); document.write( " \"1%2Ay=-3\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F1%29%281%29%29%2Ay=%28-3%2F1%29%281%2F1%29\" Multiply both sides by \"1%2F1\". This will cancel out 1 on the left side.
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\n" ); document.write( " \"y=-3%2F1\" Multiply the terms on the right side
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\n" ); document.write( " \"y=-3\" Reduce
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\n" ); document.write( " So this is the other answer
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\n" ); document.write( " \"y=-3\"<---------------------------------Other answer
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\n" ); document.write( " So our solution is
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\n" ); document.write( " \"x=-1\" and \"y=-3\"
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\n" ); document.write( " which can also look like
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\n" ); document.write( " (\"-1\",\"-3\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"2%2Ax-1%2Ay=1\"
\n" ); document.write( " \"3%2Ax%2B1%2Ay=-6\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"2%2Ax-1%2Ay=1\" (red) and \"3%2Ax%2B1%2Ay=-6\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
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\n" ); document.write( " and we can see that the two equations intersect at (\"-1\",\"-3\"). This verifies our answer.
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\n" ); document.write( " Check:
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\n" ); document.write( " Plug in (\"-1\",\"-3\") into the system of equations
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\n" ); document.write( " Let \"x=-1\" and \"y=-3\". Now plug those values into the equation \"2%2Ax-1%2Ay=1\"
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\n" ); document.write( " \"2%2A%28-1%29-1%2A%28-3%29=1\" Plug in \"x=-1\" and \"y=-3\"
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\n" ); document.write( " \"-2%2B3=1\" Multiply
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\n" ); document.write( " \"1=1\" Add
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\n" ); document.write( " \"1=1\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"-1\",\"-3\") satisfies \"2%2Ax-1%2Ay=1\"
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\n" ); document.write( " Let \"x=-1\" and \"y=-3\". Now plug those values into the equation \"3%2Ax%2B1%2Ay=-6\"
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\n" ); document.write( " \"3%2A%28-1%29%2B1%2A%28-3%29=-6\" Plug in \"x=-1\" and \"y=-3\"
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\n" ); document.write( " \"-3-3=-6\" Multiply
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\n" ); document.write( " \"-6=-6\" Add
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\n" ); document.write( " \"-6=-6\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"-1\",\"-3\") satisfies \"3%2Ax%2B1%2Ay=-6\"
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\n" ); document.write( " Since the solution (\"-1\",\"-3\") satisfies the system of equations
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\n" ); document.write( " \"2%2Ax-1%2Ay=1\"
\n" ); document.write( " \"3%2Ax%2B1%2Ay=-6\"
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\n" ); document.write( " this verifies our answer.
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