document.write( "Question 120331: I need help solving for x in the following problem: 3(cx-b)+c = ax+d/a
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document.write( "The ax+d part is all over a. \r
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document.write( "I have no idea where to start, but I know proportions can be used? \n" );
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Algebra.Com's Answer #88217 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! solving for x in the following problem: 3(cx-b)+c = ax+d/a \n" ); document.write( ": \n" ); document.write( "3(cx-b) + c = \n" ); document.write( ": \n" ); document.write( "Get rid of the denominator, multiply equation by a and you have: \n" ); document.write( "3a(cx-b) + ac = ax + d \n" ); document.write( ": \n" ); document.write( "3acx - 3ab + ac = ax + d \n" ); document.write( ": \n" ); document.write( "Add 3ab to both sides, subtract ac from both sides \n" ); document.write( "3acx = ax + 3ab + d - ac \n" ); document.write( ": \n" ); document.write( "subtract ax from both sides: \n" ); document.write( "3acx - ax = 3ab - ac + d \n" ); document.write( ": \n" ); document.write( "Factor out x on the left and factor out a on the right \n" ); document.write( "x(3ac - a) = a(3b - c) + d \n" ); document.write( ": \n" ); document.write( "Divide both sides by (3ac-a) \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( "x = |