document.write( "Question 120304: HELP!!!! Here's my problem that escapes me:\r
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document.write( "When the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number?\r
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document.write( "Thanks in advance for your help.
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document.write( "Joanne \n" );
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Algebra.Com's Answer #88175 by scott8148(6628) You can put this solution on YOUR website! let x=\"tens digit\" and y=\"units digit\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"When the digits of a two-digit number are reversed, the new number is 9 more than the original number\" \n" ); document.write( "__ 10y+x=10x+y+9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"the sum of the digits of the original number is 11\" \n" ); document.write( "__ x+y=11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=11-y __ substituting gives 10y+(11-y)=10(11-y)+y+9 __ 9y+11=119-9y __ 18y=108\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |