document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=120298>Question 120298</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have just started on equation substitutions. They are very confusing, and my entire 10th grade class is struggling. can you help me solve this substitution?\r<BR>\n" );
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document.write( "4x+y=-2  2x=-y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88171 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x+y=-2  2x=-y<BR>\n" );
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document.write( "Solve the \"simpler\" equation for \"y\":<BR>\n" );
document.write( "y = -2x<BR>\n" );
document.write( "Substitute that value of \"y\" in the other equation to solve for \"x\":<BR>\n" );
document.write( "4x+(-2x)= 2<BR>\n" );
document.write( "4x-2x = 2<BR>\n" );
document.write( "2x = 2<BR>\n" );
document.write( "x = 1<BR>\n" );
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document.write( "Substitute that into y = -2x to solve for \"y\":<BR>\n" );
document.write( "y = -2*1 = -2<BR>\n" );
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document.write( "The solution for the system is (1,-2)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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