document.write( "Question 120286: Solve each system of equations. Check by substitution\r
\n" ); document.write( "\n" ); document.write( "x - y = 3
\n" ); document.write( "x + y = -1
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Algebra.Com's Answer #88161 by MathLover1(20855)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\"x+%2B+y+=+-1\"\r
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Solved by pluggable solver: Solving a linear system of equations by subsitution

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"1%2Ax-1%2Ay=3\"
\n" ); document.write( " \"1%2Ax%2B1%2Ay=-1\"
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\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
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\n" ); document.write( " Solve for y for the first equation
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\n" ); document.write( " \"-1%2Ay=3-1%2Ax\"Subtract \"1%2Ax\" from both sides
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\n" ); document.write( " \"y=%283-1%2Ax%29%2F-1\" Divide both sides by -1.
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\n" ); document.write( " Which breaks down and reduces to
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\n" ); document.write( " \"y=-3%2B1%2Ax\" Now we've fully isolated y
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\n" ); document.write( " Since y equals \"-3%2B1%2Ax\" we can substitute the expression \"-3%2B1%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
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\n" ); document.write( " \"1%2Ax%2B1%2Ahighlight%28%28-3%2B1%2Ax%29%29=-1\" Replace y with \"-3%2B1%2Ax\". Since this eliminates y, we can now solve for x.
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\n" ); document.write( " \"1%2Ax%2B1%2A%28-3%29%2B1%281%29x=-1\" Distribute 1 to \"-3%2B1%2Ax\"
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\n" ); document.write( " \"1%2Ax-3%2B1%2Ax=-1\" Multiply
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\n" ); document.write( " \"1%2Ax-3%2B1%2Ax=-1\" Reduce any fractions
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\n" ); document.write( " \"1%2Ax%2B1%2Ax=-1%2B3\"Add \"3\" to both sides
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\n" ); document.write( " \"1%2Ax%2B1%2Ax=2\" Combine the terms on the right side
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\n" ); document.write( " \"2%2Ax=2\" Now combine the terms on the left side.
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\n" ); document.write( " \"cross%28%281%2F2%29%282%2F1%29%29x=%282%2F1%29%281%2F2%29\" Multiply both sides by \"1%2F2\". This will cancel out \"2%2F1\" and isolate x
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\n" ); document.write( " So when we multiply \"2%2F1\" and \"1%2F2\" (and simplify) we get
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\n" ); document.write( " \"x=1\" <---------------------------------One answer
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\n" ); document.write( " Now that we know that \"x=1\", lets substitute that in for x to solve for y
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\n" ); document.write( " \"1%281%29%2B1%2Ay=-1\" Plug in \"x=1\" into the 2nd equation
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\n" ); document.write( " \"1%2B1%2Ay=-1\" Multiply
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\n" ); document.write( " \"1%2Ay=-1-1\"Subtract \"1\" from both sides
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\n" ); document.write( " \"1%2Ay=-2\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F1%29%281%29%29%2Ay=%28-2%2F1%29%281%2F1%29\" Multiply both sides by \"1%2F1\". This will cancel out 1 on the left side.
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\n" ); document.write( " \"y=-2%2F1\" Multiply the terms on the right side
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\n" ); document.write( " \"y=-2\" Reduce
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\n" ); document.write( " So this is the other answer
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\n" ); document.write( " \"y=-2\"<---------------------------------Other answer
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\n" ); document.write( " So our solution is
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\n" ); document.write( " \"x=1\" and \"y=-2\"
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\n" ); document.write( " which can also look like
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\n" ); document.write( " (\"1\",\"-2\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"1%2Ax-1%2Ay=3\"
\n" ); document.write( " \"1%2Ax%2B1%2Ay=-1\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"1%2Ax-1%2Ay=3\" (red) and \"1%2Ax%2B1%2Ay=-1\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
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\n" ); document.write( " and we can see that the two equations intersect at (\"1\",\"-2\"). This verifies our answer.
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\n" ); document.write( " Check:
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\n" ); document.write( " Plug in (\"1\",\"-2\") into the system of equations
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\n" ); document.write( " Let \"x=1\" and \"y=-2\". Now plug those values into the equation \"1%2Ax-1%2Ay=3\"
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\n" ); document.write( " \"1%2A%281%29-1%2A%28-2%29=3\" Plug in \"x=1\" and \"y=-2\"
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\n" ); document.write( " \"1%2B2=3\" Multiply
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\n" ); document.write( " \"3=3\" Add
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\n" ); document.write( " \"3=3\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"1\",\"-2\") satisfies \"1%2Ax-1%2Ay=3\"
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\n" ); document.write( " Let \"x=1\" and \"y=-2\". Now plug those values into the equation \"1%2Ax%2B1%2Ay=-1\"
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\n" ); document.write( " \"1%2A%281%29%2B1%2A%28-2%29=-1\" Plug in \"x=1\" and \"y=-2\"
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\n" ); document.write( " \"1-2=-1\" Multiply
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\n" ); document.write( " \"-1=-1\" Add
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\n" ); document.write( " \"-1=-1\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"1\",\"-2\") satisfies \"1%2Ax%2B1%2Ay=-1\"
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\n" ); document.write( " Since the solution (\"1\",\"-2\") satisfies the system of equations
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\n" ); document.write( " \"1%2Ax-1%2Ay=3\"
\n" ); document.write( " \"1%2Ax%2B1%2Ay=-1\"
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\n" ); document.write( " this verifies our answer.
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