document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=120260>Question 120260</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1565771346/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> PLEASE HELP ME ANSWER THIS PROBLEM:\r<BR>\n" );
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document.write( "-2[(-K-3)(-2)-3]=(-3-3K)(-2)TO THE POWER OF 3 THEN MINUS 3 TO THE POWER OF 2<BR>\n" );
document.write( "THANK YOU SO MUCH! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88133 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -2[(-k-3)(-2)-3]=(-3-3k)(-2)^3-3^2<BR>\n" );
document.write( "-2[(2k+6)-3]=(-3-3k)(-8)+9<BR>\n" );
document.write( "-2[2k+6-3]=24+24k+9<BR>\n" );
document.write( "-2[2k+3]=33+24k<BR>\n" );
document.write( "-4k-6=33+24k<BR>\n" );
document.write( "-4k-24k=33+6<BR>\n" );
document.write( "-28k=43<BR>\n" );
document.write( "k=43/-28<BR>\n" );
document.write( "k=-43/28 answer. </SPAN>\n" );
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